(4x-2)(x+3)=4x^2+9

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Solution for (4x-2)(x+3)=4x^2+9 equation: 



(4x-2)(x+3)=4x^2+9

We move all terms to the left:

(4x-2)(x+3)-(4x^2+9)=0

We get rid of parentheses

-4x^2+(4x-2)(x+3)-9=0

We multiply parentheses ..

-4x^2+(+4x^2+12x-2x-6)-9=0

We get rid of parentheses

-4x^2+4x^2+12x-2x-6-9=0

We add all the numbers together, and all the variables

10x-15=0

We move all terms containing x to the left, all other terms to the right

10x=15

x=15/10

x=1+1/2

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